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Prove that 7√5 is irrational number

Answer» Let us assume that\xa07√5\u200b\xa0is rational numberHence\xa07√5\u200b\xa0can be written in the form of\xa0a/b\xa0where\xa0a,b(b is not equal to 0)\xa0are co-prime⟹7√5\u200b=a/b⟹√5\u200b=a/7bBut here\xa0√5\u200b\xa0is irrational and\xa0a\u200b/7b\xa0is rationalas\xa0Rational is not equal to IrrationalThis is a contradiction\xa0so\xa07√5\u200b\xa0is a irrational number


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