Prove that √7 be irrational

1.	Prove that √7 be irrational
Answer» Sry yrr glti se 7 ki jgh 3 ho gya aap 7 kr lena 3 ki jgh baki same ese hi h Let us assume to the contrary ,that √3 is rational.That is,we can find integers a and b(#0 )such that√3=a/b.Suppose a and b have a common factor other tha 1,then we can divide by the common factor , and assume that a and b are coprime.So,b√3=aSquaring both sides,a2 is divisible by 3 that a is also divisible by 3So,we can write a=3c for some integer c.Substituting for a,we get 3b2= 9c2.This means that b2 is divisible by 3,and so b is also divisible by 3 ..a and b have at least 3 as a common factor.But this contradicts the fact that a and b are coprime ..This contradiction has arisen because of our incorrect assumption that √3 is rational..So,we conclude that √3 is irrational..??

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