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prove that √7 is irrational (plz write step by step) |
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Answer» Let root 7 be a rational numberThen root 7 is equal to p upon qwhere p and q are coprime integers and q is not equals to zero........By squaring both sides....7=p²/q²........q²=p²/7If 7 divides p² 7 also divides p.....Let p=7c......q²=49c²/7.........q²=7c².........q²/7=c²......If 7 q² then 7 also divides q......Hence p and q are not coprime integers.....Our assumption was wrong that √7 is a rational number........Root 7 is not a rational number.....Root 7 is an irrational number what types of Questions have chances to come in board xams from ch 1 You can see in text book page 13...there it is proved that root3 is irrational....u can get help from there |
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