1.

Prove that 8x can not end with digit O, for any natural no. n.

Answer» Yes 8*n will not end with zero because , the number will end with zero then it\'s factors should 2and5
We know 8n\xa0= (23)n\xa0= 23nIf 8n\xa0end with zero then 10 is factor of 8n.\xa08n\xa0= 23n\xa0=\xa0(5)(2)\xa05 is factor of 2, which is a contradictionSo, our assumption is wrong. Hence 8n\xa0cannot end with zero.


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