Prove that area of rhombus is equal to half of product of its diagonal

1.	Prove that area of rhombus is equal to half of product of its diagonals
Answer» Let ABCD be a rhombus whose diagonals are AC and BD.Then, Area of rhombus ABCD= Area of {tex}\\bigtriangleup{/tex}ABD + Area of {tex}\\bigtriangleup{/tex}CBD{tex}={(BD)(AO)\\over2}+{(BD)(OC)\\over2}{/tex} . .[Diagonals of a rhombus are perpendiculars to each other]{tex}={(BD)\\over2}(AO+OC)={(BD)(AC)\\over2}{/tex}={tex}1\\over2{/tex} product of the lengths of its diagonals.

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