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Prove that cos²A+sin²A=1

Answer» Cos A=B/H sinA=P/HCos²A+sin²AB²/H² + P²/+H² B²+P²/H² H²/H² =1
In triangle ABC,right Angled at B we have,AB^2+BC^2=AC^2Dividing each term of (1),we getAB^2/AC^2 + BC^2/AC^2 = AC^2/AC^2That is -(cosA)^2+ sinA


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