Prove that (cosec theta +cot theta) square =sec theta +1/sec theta-1

1.	Prove that (cosec theta +cot theta) square =sec theta +1/sec theta-1
Answer» {(1/sin)+(cos/sin)}² ={(1+cos)/sin}² =(1+cos)²/sin²=(1+cos)²/(1-cos²)=(1+cos)(1+cos)/(1-cos)(1+cos)=(1+cos)/(1-cos)=(1+1/sec)/(1-1/sec)=(sec+1)/(sec-1)

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