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| 1. |
Prove that (cosecΦ - sinΦ)(secΦ - cosΦ)(tanΦ + cotΦ) = 1 |
| Answer» (1by sin theta-sin theta) (1by cos theta- cos) (sin by cos +cos by sin) =(1-sin square theta/sintheta) (1-cos square theta/cos theta)[ (sin sq. +cos sq theta) /sin cos] =(cos sq. /sin) (sin sq. Theta/cos theta) (1/sin cos) =1 | |