Prove that √n is irrational number

1.	Prove that √n is irrational number
Answer» Let √n be the rational number and take the contradiction if √n is a rational then it is in the form of P/q, squaring on both sides (√n)2= p/q)2 after squaring q2= p2/n ,where n divides p2 and also n divides p this process also takes place with q after that p and q have factor 2 .So our contradiction have gone wrong becoz rational no.consists of co primes no. It is proved that √n is an irrational no.

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