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Prove that product of two consecutive integers is divisible by 2

Answer» n(n+1)=n 2 +1=((n+1)−1)(n+1)=(n+1) 2 −(n+1)So if (n+1) is an even no (n+1) 2 is even and diff of even is always even is (n+1).If odd then (n+1) 2 is odd and diff of odd is always even So n(n+1) is always even and divisible by 2.
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