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Prove that root 2+root 3 is an irrational no.

Answer» Yo
Let √2 + √3 = (a/b) is a rational no.On squaring both sides , we get2 + 3 + 2√6 = (a2/b2)So,5 + 2√6 = (a2/b2) a rational no.So, 2√6 = (a2/b2) – 5Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no.So, my contradiction is wrong.So, (√2 + √3) is an irrational no.


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