Prove that SEC∅+1-TAN∅ / SEC∅+1+TAN∅ = 1-SIN∅ / COS∅

1.	Prove that SEC∅+1-TAN∅ / SEC∅+1+TAN∅ = 1-SIN∅ / COS∅
Answer» I am taking theta as A=SecA-tanA+(sec^2A-tan^2A)/secA+1+tanA {replacing 1using identity sec2A-tan2A=1}=secA-tanA(secA+tanA+1)/secA+1+tanA=secA-tanA=1/cosA - sinA/cosA=1-sinA/cosA Missing you a lot???????????????? ???????????????? Raj ???????? Profile name mein Suman kon h jii Hiiiiiiiiiiiiiii jii

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