1.

Prove that sec A (1-sin A ) ( sec A + tan A) =1

Answer» SecA(1-sinA) (secA+tanA)=1/cosA(1-sinA) (1/cosA +sinA/cosA)=1/cosA(1-sinA) (1+sinA/cosA)=1/cosA(1-sinA) 1/cosA(1+sinA)=1/cos squareA (1-sin square A)=1/cos square A × cos square A=1


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