Prove that Sec power 4 theta - secsquare theta = tan power4 +tansquare

1.	Prove that Sec power 4 theta - secsquare theta = tan power4 +tansquare theta
Answer» Sec4A - Sec2A = tan\xa04A + tan\xa02ASec4A - Sec2A = Sec2A( Sec2A-1) = (1+tan2A) tan2A = tan\xa02A+ tan\xa04A Sec⁴A- sec² = sec²( sec² - 1 ) = sec²tan² = 1/cos²sin²/cos² = sin²sec⁴ LHS.. Now, tan⁴+ tan² = tan² (tan²+1) = tan²sec² = sin²/cos²1/cos² = sin²sec⁴ = RHS. Hence LHS=RHS.

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