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Prove that secA (1-sin A)(secA plus tan A) is equal to 1

Answer» 1/sina(1-sin a)(seca+ tan a)(1/cos a - sin a/ cos a)(sec a+ tan a)(Sec a - tan a)(sec a+ tan a)Sec²a- tan²a= 1. (1+ tan²a=sec²a)Hence LHS =RHS
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