1.

Prove that (secA+tanA-1)(secA-tanA+1)=2/cotA

Answer» Atleast answer to mila mujhe
Yup, se...here ..---> (secA+tanA-1)(secA-tanA+1) -----> (secA +tanA-1){secA-(tanA-1)}..................... ----->sec square A - ( tanA - 1)square ................... ------> sec square A-(tan square A+1-2tanA) ........ ----> sec square A-tan square A - 1+ 2 tanA......... ----> 1-1+2tanA........ ----> 2tanA..... ------> 2/ cotA.. HENCE PROVED......☺☺


Discussion

No Comment Found