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Prove that sin 6theta +cos6theta =(1-3sin²theta cos²theta)

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Sin 6 theta + cos 6 theta Taking lhs:-(Sin cube theta) square + (cos cube theta )square By using identity a cube + b cube is equal to a + b whole cube minus 3 ab into a + bSo(Sin square theta )cube + (cos square theta) cube = (sin square theta + cos square theta) whole cube - 3 sin square theta cos square theta ( sin square theta + cos square theta) So 1- 3 sin square theta cos square theta L.H.S =R.H.S. H.P


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