Prove that sin square tita plus cos square tita is equals to one

1.	Prove that sin square tita plus cos square tita is equals to one
Answer» as per puthgoras\xa0theoren\xa0in right angle triangle:base2\xa0+ height\xa02\xa0= hypo 2devide\xa0both sides by hypo2(base / hypo)2 +( height/ hypo)2 =1sin2\xa0Θ + cos\u200b\u200b\u200b\u200b\u200b\u200b\u200b2\xa0Θ\u200b\u200b\u200b\u200b\u200b\u200b\u200b = 1\xa0\xa0

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