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| 1. |
Prove that (sin theta+1+cos theta)(sin theta-1+cos theta)(sec theta cosec theta)=2 |
| Answer» LHS={(sin Φ+cos Φ)+1}{(sin Φ+cos Φ)-1}(sec Φ*cosec Φ)={(sin Φ + cos Φ)^2 -1}(sec Φ*cosec Φ)=(sin^2Φ+cos^2Φ+2sinΦcosΦ-1)(secΦ*cosecΦ)=(2sinΦcosΦ)(1/cosΦsinΦ)=2=RHS | |