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| 1. |
Prove that :sinA-2sin3A/2cos3A-cosA=tanA |
| Answer» sinA (1-2sin2A)/cosA ( 2cos2A -1)SinA (1-2 (1-cos2A)/cosA (2cos2A -1)=sinA (2cos2A -1)/cosA ( 2cos2A -1)=sinA/ cosA =tanA | |