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| 1. |
Prove that :tanθ+sinθ/tanθ-sinθ\u200b=secθ+1/secθ-1\u200b |
| Answer» (tanΘ + sinΘ)/(tanΘ - sinΘ)= [(sinΘ/cosΘ + sinΘ)] / [sinΘ/cosΘ - sinΘ]= sinΘ(1/cosΘ + 1) / sinΘ(1/cosΘ - 1)= sinΘ(secΘ + 1) / sinΘ)(secΘ - 1)= (secΘ + 1) / (sec Θ - 1)This is the only way the answer can be typed. Hope u understand. | |