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| 1. |
Prove that the point (0,0) (5,5) (-5,5) are the vertices of right vertices triangle. |
| Answer» Let A= (0,0) , B = (5,5) and C = (-5,5)AB = √(5-0)2\xa0+(5-0)2\xa0= √25+25 = √50BC = √(-5-5)2\xa0+ (5-5)2\xa0= √(-10)2\xa0+0 = √100AC = √(-5-0)2\xa0+(5-0)2\xa0= √(-5)2\xa0+(5)2\xa0= √25+25 = √50BC2\xa0= AB2+AC2(√100)2\xa0= (√50)2\xa0+(√50)2100= 50+50100=100So the given points are vertices of right angled triangle. | |