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Prove that the points (2,5) , (4,6) , (8,8) are collinear using section formula |
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Answer» Let (x1=2) | (x2=4) | (x3=8) similarly (y1=5) | (y2=6) and (y3=8)Now, The section formula is :{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=0}Putting the value of x n y we get:2(6-8)+4(8-5)+8(5-6)=02*-2+4*3+8*-1=0-4+12-8=0Since the given points are collinear. ? Cvnmud |
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