1.

Prove that the points (3.0).(6.4).(-1.3) are the vertices of the right angled isosceles taingle

Answer» AB^2 = (3-6)^2 + (0-4)^2 = 9+16= 25BC^2 = (3+1)^2 + (0+3)^2 =16+9 =25AC^2 = (6+1)^2 + (4-3)^2 = 49+1 = 50Since AC^2 = AB^2 + BC^2 Triangle ABC is a rt. Triangle


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