Prove that the product of two consecutive posetive integers is divisib

1.	Prove that the product of two consecutive posetive integers is divisible by two
Answer» Let two consecutive + ve integer r n and n+1nn+1=n2+ nLet n=2q so (2q)2 + 2qThen we take common from it 2 then we have2(2q2+q)Divide by 2 then we have2q2+qRemainder is 0 so it is completely divisibleHence prooved... Take a example21=2and then divive by 2 so 2/2=1So it is completely devisible

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