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Prove that the tangent drawn at end point of a chord of a circle make equal angle with the chord

Answer» Let AB be a chord of a circle whose centre is 0. Let PA and PB be tangents to the circle at A and B respectively. Then,PA = PB [{tex}\\because{/tex} Tangent segments from an external point to a circle are equal]In\xa0{tex}\\triangle{/tex} PAB,{tex}\\angle{/tex}PAB = {tex}\\angle{/tex}PBA [Angle opposite to equal sides of a triangle are equal]


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