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| 1. |
Prove under root 5 is irrational? |
| Answer» Let us assume that √5 is a rational number.we know that the rational numbers are in the form of p/q form where p,q are integers.so, √5 = p/q p = √5qwe know that \'p\' is a rational number. so √5 q must be rational since it equals to pbut it doesnt occurs with √5 since its not an integertherefore, p =/= √5qthis contradicts the fact that √5 is an irrational numberhence our assumption is wrong and √5 is an irrational number.\xa0 | |