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Q .If a dice is tossed 3 times then find the probability getting at least 3 on a dice |
| Answer» I assume you mean “IF a die is tossed three times, what is the probability of no fives?” Die #1 can do so with probability 5 / 6 (meaning, no fives). Ditto for #2, #3. Hence, the required probability is (5/6)*(5/6)*(5/6) = 125/216, which is almost 58%. | |