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Q. the angles of triangle are in A.P. The greatest angle is twice the least. Find all the angles |
| Answer» Let the three angles of triangle which are in A.P. be a - d, a, a + dNow, sum of the angles = 180°{tex}\\Rightarrow{/tex}\xa0a - d + a+ a + d =\xa0180°{tex}\\Rightarrow{/tex}\xa03a = 180°{tex}\\Rightarrow{/tex}\xa0a = 60°It is given that,a + d= 2(a - d){tex}\\Rightarrow{/tex}\xa0a + d = 2a - 2d{tex}\\Rightarrow{/tex}\xa0a = 3d{tex}\\Rightarrow{/tex}\xa060° = 3d{tex}\\Rightarrow{/tex}\xa0d =\xa020°Thus, the angles of triangle are 40°, 60°, 80°. | |