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Question number 8 of Exercise 4.3 |
| Answer» D=360 km Original speed =x km /hIf speed=x+5 km/hATQSpeed=distance÷timeSO, Original time=360 ÷xAnd New time=360÷x+5Now as per ques Original time - 1=new time Or Original time - new time =1So,(360÷x) - (360÷x+5) =1 | |