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Refer to Q 10 and Q11, and calculate specific volume.(a) 6.51 × 10^-5 m^3/N(b) 6.78 × 10^-5 m^3/N(c) 6.45 × 10^-5 m^3/N(d) 6.57 × 10^-5 m^3/NThe question was asked by my college director while I was bunking the class.My question comes from Classification of Fluids in portion Fluid Flow and Mixing of Bioprocess Engineering

Answer»

Right OPTION is (d) 6.57 × 10^-5 m^3/N

The EXPLANATION: Specific VOLUME = 1/(Specific weight)

= 1/(1.52×104 N/m^3)

= 6.57 × 10^-5 m^3/N.



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