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Refer to Q12 and, calculate OTR. (Given: kLa = 169 mmol O2/ 1 hr atm, P* = 0.0263 atm and PO2 = 0.21 atm).(a) 30.05 mmoles O2 / liter hr(b) 31.05 mmoles O2 / liter hr(c) 20.05 mmoles O2 / liter hr(d) 21.05 mmoles O2 / liter hrThis question was addressed to me during an interview.This interesting question is from Measurement of KLa in portion Mass Transfer of Bioprocess Engineering

Answer»

Right CHOICE is (b) 31.05 mmoles O2 / liter HR

To EXPLAIN I would say: OTR = KLA(PO2 – P*)

= 169 mmol O2 / 1 hr ATM(0.21- 0.0263) atm

= 31.05 mmoles O2 / liter hr.



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