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Refer to Q6, and calculate the power dissipated per unit mass of fluid.(a) 0.050 m^2 s^-3(b) 0.042 m^2 s^-3(c) 0.040 m^2 s^-3(d) 0.052 m^2 s^-3I had been asked this question in an interview for internship.I need to ask this question from Role of Shear in Stirred Fermenters topic in section Fluid Flow and Mixing of Bioprocess Engineering

Answer»

Right CHOICE is (d) 0.052 m^2 s^-3

Explanation: \(\lambda^4 = \FRAC{v^3}{\varepsilon}\)

\(\varepsilon = \frac{v^3}{λ^4}\)

Therefore,

\(\varepsilon = \frac{(1.29×10^{-6})^3 \,m^6 \,s^{-3}}{(8×10^{-5})^4 m^4}\) = 0.052 m^2 s^-3.



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