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Root √5 is irrational |
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Answer» Let us assume that √5 is rational, then it will be =a/ba and be are coprime numbers. √5=a/bSquaring both sides5=a²/b²5b²=a²It means 5 will divide a² and also a. 5 will divide a for some integer c5c=a (squaring both sides) 25c² = a²So 25c²=5b²5c²=b²It contradicts that a and b are coprime, our assumption was wrong and √5 is irrational How i can solve it Yes bro |
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