Saved Bookmarks
| 1. |
Sec+tan=mSec-tan=nShow that mn=1 |
| Answer» Given secA +tanA=m and secA-tanA=nTo prove:- mn=1L.H.S. mn=(secA+tanA)(secA-tanA) = sec2A - tan2A [by using identity (a+b)(a-b)=a2\xa0- b2 ] = 1+tan2A - tan2A [by using identity sec2A=1+tan2A ] = 1=R.H.S. H.Proved | |