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Sec theta ( 1-sin theta) ( sec theta+tan theta)=1 |
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Answer» = secA (1-sinA) (secA+tanA)= secA (secA + tanA - sinA secA - sinA tanA)= 1/cosA [1/cosA + sinA/cosA - sinA/cosA - sin²A/cosA]= 1/cosA [1/cosA - sin²A/cosA]= 1/cosA [(1-sin²A)/cosA]= 1/cosA [cos²A/cosA]=1 I have solved this questio,but how can I send it to you? |
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