InterviewSolution
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| 1. |
Sec theta/ cot theta+tan theta = |
| Answer» [email\xa0protected]/[email\xa0protected][email\xa0protected] = 1/[email\xa0protected]([email\xa0protected]/[email\xa0protected][email\xa0protected]/[email\xa0protected]) = 1/[email\xa0protected]/(sin²@+cos²@)/[email\xa0protected]@ (:- sin²@+cos²@=1) 1/[email\xa0protected]/1/[email\xa0protected]@ = [email\xa0protected]@/[email\xa0protected] = [email\xa0protected] ans | |