1.

SecA(1-sinA) (secA+tanA=1

Answer» 1/cosA(1-sinA)(1/cosA+sinA/cosA)=((1-sinA)/cosA)((1+sin)/cosA)=((1-sinA)(1+sinA))/cos2A=(1-sin2A)/cos2A=Cos2a/cos2A=1


Discussion

No Comment Found