InterviewSolution
Saved Bookmarks
| 1. |
Show root 2 as an irrational number |
|
Answer» Given √2 is irrational number.Let √2 = a / b wher a,b are integers b ≠ 0we also suppose that a / b is written in the simplest formNow √2 = a / b⇒ 2 = a2 / b2\xa0⇒ 2b2 = a2∴ 2b2 is divisible by 2⇒ a2 is divisible by 2 ⇒ a is divisible by 2 ∴ let a = 2ca2 = 4c2⇒ 2b2 = 4c2 ⇒\xa0b2 = 2c2∴ 2c2 is divisible by 2∴ b2 is divisible by 2∴ b is divisible by 2∴ a are b are divisible by 2 .this contradicts our supposition that a/b is written in the simplest formHence our supposition is wrong∴ √2 is irrational number. You will find your answer in maths NCERT Book........It is very... difficult to type here Yup u will find answer in ur ncert book..... It is difficult to type here.... Bohat bada h..yaha nhi bta skte...ncert me dekho Refer to your ncert book.. |
|