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| 1. |
Show that 3√2 is irrational. |
| Answer» Let us assume to the contrary that 3√2 is a rational This is we can find coprime a and b (b is not equal to 0) such that 3√2=a/bRearranging we get √2=a/3bSince 3,a and b are. Integer a/3b is rational and so √2 is rationalBut this contradicts the fact that √2 is irrationalSo we conclude that 3√2 is irrational | |