Show that 9 to the power of m cannot end with digit 2 where m is any n

1.	Show that 9 to the power of m cannot end with digit 2 where m is any natural number
Answer» Let that 9 to the power m is equal to 2*n(n is commen between 2 and 9)9^m=2×n => (3×3)^m=2×nSo therefore 2 is not a factor of 9 :. 9to the power of m is cannot end with digit 2.

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