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| 1. |
Show that any number of form 4^n, n€N can never end with digit 0. |
| Answer» {tex}{4^n} = {\\left[ {{2^2}} \\right]^n} = {2^{2n}}{/tex}It does not contains \'5\'. So\xa0{tex}{4^n},n \\in N{/tex} can never end with the digit 0 | |