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Show that \(\begin{vmatrix}sin\,10° & -cos\,10° \\[0.3em]sin\,80° &cos\,80°\end{vmatrix}\) = 1 |
Answer» Using, sin(A+B) = sin A × cos B + cos A × sin B ⇒ |A| = sin10° × cos80° + cos10° x sin80° |A| = sin(10 + 80)° |A| = sin90° |A| = 1 Hence Proved. |
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