Show that n2_1 is divisible by 8

1.	Show that n2_1 is divisible by 8
Answer» n is an odd no.n=4q+1 and n=4q+3n^2-1=(4q+1)^2-1. And. n^2-1=(4q+3)^2-1 =16q^2+8q+1-1. =16q^2+24q+9-1 =8(2q^2+q) =16q^2+24q+8 =8m. =8(2q^2+3q+1) =8m

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