Saved Bookmarks
| 1. |
Show that p square will leave a remainder 1 when divided by 8 if P is an odd positive integer |
| Answer» P = 2n + 1 where n = 0, 1, 2, 3, 4, ...=> p² = 4n² + 4n + 1= 4(n² + n) + 1= 4n(n+1) + 1but n(n+1) is even because if n is odd, n+1 is even - otherwise n is eventherefore 4n(n+1) + 1 = 8m + 1 where m is an integer.=> p² = 1 | |