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Show that root2 is irrational |
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Answer» Let us assume √2 is rational then √2=a/b (a and b are Co primes) Squaring both sides (√2)2=a2/b2 then 2b2 =a2b2=a2/2a/2 (using theorem 1.3)a=2c a2=4c22b2=4c2b2=2c22/b22/bFrom this we conclude that a and b have 2 common factor but this contradicts the fact that a and b have no common factor other than 1 hence our assumption is wrong √2 is irrational . Thank u by contradicting.....first u have to think it a integar...then solve |
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