Saved Bookmarks
| 1. |
Show that the polynomial x^2-6x+12 has no zeroes |
| Answer» x2\xa0- 6x + 12Here, a = 1, b = -6 and c = 12D = b2\xa0- 4acD = (-6)2\xa0- 4(1)(12)D = 36 - 48D = -12Hence, D < 0Therefore, there exists no real root of the equation. | |