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Show that the sequence given by `T_(n)=(2xx3^(n))` for all `n in N` is a GP. Find its first term and the common ratio. |
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Answer» We have `T_(n)=(2xx3^(n))` and `T_(n+1)=(2xx3^(n+1))`. `:. T_(n+1)/T_(n)=(2xx3^(n+1))/(2xx3^(n))=3` (constant) for all `n in N`. Also, `T_(1)=(2xx3^(1))=(2xx3)=6` `:.` the first term `=6` and the common ratio `=3`. |
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