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Show that there exists no rational number whose square is 5 |
| Answer» Given,Prove that there is no rational number whose square is\xa0Let\'s assume that\xa0, where\xa0\xa0and\xa0\xa0and\xa0are co-prime.Then we have,So,⇒\xa0This implies that\xa0\xa0is even.Then,So,⇒\xa0⇒Thus,⇒⇒Then,∴\xa0which contradicts\xa0\xa0and\xa0\xa0being co-prime.Therefore,\xa0\xa0is irrational. | |