1.

Show that x=bc/ad is a solution of the quadratic equation ad2(ax/b+2c/d)x+bc2=0.

Answer» We have, {tex}ad^2x ({a \\over b}x + {2c \\over d}) + c^2b =0{/tex}{tex}\\implies {a^2d^2 \\over b}x^2 + 2acdx + c^2b = 0{/tex}{tex}\\implies {a^2d^2 \\over b}x^2 + acdx +acdx + c^2b = 0{/tex}{tex}\\implies adx({ad \\over b}x+c) + bc({ad \\over b}x + c) = 0{/tex}{tex}\\implies (adx+ bc) ({ad \\over b}x + c) = 0{/tex}Either adx + bc =0 or {tex}({ad \\over b}x + c) = 0{/tex}{tex}\\implies x = -{bc \\over ad}{/tex}Hence, {tex}x = -{bc \\over ad}{/tex} is the requirreed solution.


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